In: Statistics and Probability
For of a bell-shaped data with mean of 100 and standard deviation of 16, approximately
a)0.15% of the values lies below __________
b)68% of the middle values lies between: _____________
c)2.5% of the values lies above: ____________
d)0.15% of the values lies above: ____________
Solution:
Given: a bell-shaped data is with mean of 100 and standard deviation of 16.
That is: and
Since data is bell shaped , we need to use Empirical rule to find x values for given percentage values.
Empirical rule is:
1) 68% of the data falls within 1 standard deviation from mean
2) 95% of the data falls within 2 standard deviation from mean
3) 99.7% of the data falls within 3 standard deviation from mean
.
Part a) 0.15% of the values lies below____?
Since 99.7% values are within 3 standard deviation from mean, then 100-99.7=0.30% values are outside the 3 standard deviation from mean.
Thus 0.30/2=0.15% values are below 3 standard deviation from mean and remaining 0.15% values are above 3 standard deviation from mean.
Thus find:
Thus 0.15% of the values are below 52.
Part b) 68% of the middle values lies between:______?
According to Empirical rule 68% of the data falls within 1 standard deviation from mean
Thus find:
and
Thus 68% of the middle values lies between 84 and 116
Part c) 2.5% of the values lies above:____?
According to Empirical rule 95% of the data falls within 2 standard deviation from mean
then 100 - 95 = 5% of values fall outside the 2 standard deviation from mean.
That is: 5%/2=2.5% of values fall below the 2 standard deviation from mean and remaining 2.5% of values fall above the 2 standard deviation from mean.
Since we have to find 2.5% of the values lies above, find:
Thus 2.5% of the values lies above 132.
Part d) 0.15% of the values lies above:_______?
Since 99.7% values are within 3 standard deviation from mean, then 100-99.7=0.30% values are outside the 3 standard deviation from mean.
Thus 0.30/2=0.15% values are below 3 standard deviation from mean and remaining 0.15% values are above 3 standard deviation from mean.
Thus find:
Thus 0.15% of the values are above 148.