Question

In: Statistics and Probability

When the number of trials, n, is large, binomial probability tables may not be available. Furthermore,...

When the number of trials, n, is large, binomial probability tables may not be available. Furthermore, if a computer is not available, hand calculations will be tedious. As an alternative, the Poisson distribution can be used to approximate the binomial distribution when n is large and p is small. Here the mean of the Poisson distribution is taken to be μ = np. That is, when n is large and p is small, we can use the Poisson formula with μ = np to calculate binomial probabilities; we will obtain results close to those we would obtain by using the binomial formula. A common rule is to use this approximation when n / p ≥ 500.

To illustrate this approximation, in the movie Coma, a young female intern at a Boston hospital was very upset when her friend, a young nurse, went into a coma during routine anesthesia at the hospital. Upon investigation, she found that 12 of the last 31,000 healthy patients at the hospital had gone into comas during routine anesthesias. When she confronted the hospital administrator with this fact and the fact that the national average was 5 out of 62,000 healthy patients going into comas during routine anesthesias, the administrator replied that 12 out of 31,000 was still quite small and thus not that unusual.

Note: It turned out that the hospital administrator was part of a conspiracy to sell body parts and was purposely putting healthy adults into comas during routine anesthesias. If the intern had taken a statistics course, she could have avoided a great deal of danger.)

(a) Use the Poisson distribution to approximate the probability that 12 or more of 31,000 healthy patients would slip into comas during routine anesthesias, if in fact the true average at the hospital was 5 in 62,000. Hint: μ = np = 31,000 (5/62,000) = 2.5. (Leave no cell blank. You must enter "0" for the answer to grade correctly. Do not round intermediate calculations. Round final answer to 5 decimal places.)

Solutions

Expert Solution

When the number of trials, n, is large, binomial probability tables may not be available.

Furthermore, if a computer is not available, hand calculations will be tedious.

As an alternative, the Poisson distribution can be used to approximate the binomial distribution when n is large and p is small.

Here the mean of the Poisson distribution is taken to be μ = np

That is, when n is large and p is small, we can use the Poisson formula with μ = np to calculate binomial probabilities , we will obtain results close to those we would obtain by using the binomial formula.

A common rule is to use this approximation when n / p ≥ 500.

To calculate : the probability that 12 or more of 31,000 healthy patients would slip into comas during routine anesthesias.

Now,

Let X be the random variable.

Hence X ~ Bin (n, p) ~ Bin (31000, p)

Here p = 5/62000.

By using Poisson distribution ,

Therefore the probability that 12 or more of 31,000 healthy patients would slip into comas during routine anesthesias is 0.00001


Related Solutions

Determine the indicated probability for a binomial experiment with the given number of trials n and...
Determine the indicated probability for a binomial experiment with the given number of trials n and the given success probability p. Then find the mean, variance, and standard deviation. 18. n = 10, p = 0.2, P(1) 20. n = 14, p = 0.3, P(8) 22. n = 6, p = 0.8, P(6) 24. n = 15, p = 0.9, P(14 or more) 26. n = 30, p = 0.9, P(More than 27)
In the binomial probability distribution, let the number of trials be n = 4, and let...
In the binomial probability distribution, let the number of trials be n = 4, and let the probability of success be p = 0.3310. Use a calculator to compute the following. (a) The probability of three successes. (Round your answer to three decimal places.) (b) The probability of four successes. (Round your answer to three decimal places.) (c) The probability of three or four successes. (Round your answer to three decimal places.)
Binomial distributions are approximately normal when the number of trials is large, and the probaility of...
Binomial distributions are approximately normal when the number of trials is large, and the probaility of success is not near zero or one. A player flips an unbiased coin 1,296 times. a. What is the probability of the coin landing on heads between 612 and 684 times?
We know that based on the Binomial distribution, probability of x successes in n trials when...
We know that based on the Binomial distribution, probability of x successes in n trials when the probability of success is (p) can be calculated by multiplying Combinations of n items x by x, multiplied by the probability of success (p) raised to (x) and multiplied by (1-p) raised to (n-x). 1. If probability of having a child who will study business in college (probability of success) is 0.25, what is the probability of a family with 6 children will...
Assume that a procedure yields a binomial distribution with n trials and the probability of success...
Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean mu and standard deviation sigma. ?Also, use the range rule of thumb to find the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma. n n=1510?, p=4/ 5
Let N be a binomial random variable with n = 2 trials and success probability p...
Let N be a binomial random variable with n = 2 trials and success probability p = 0.5. Let X and Y be uniform random variables on [0, 1] and that X, Y, N are mutually independent. Find the probability density function for Z = NXY . Hint: Find P(Z ≤ z) for z ∈ [0, 1] by conditioning on the value of N ∈ {0, 1, 2}.
assume that a procedure yields a binomial distribution with n=7 trials and the probability of success...
assume that a procedure yields a binomial distribution with n=7 trials and the probability of success of p=0.30 use a binomial probability table to find the probability that the number of successes is exactly 4, at least2 and at most 3
assume that a procedure yields a binomial distribution with n=7 trials and the probability of success...
assume that a procedure yields a binomial distribution with n=7 trials and the probability of success of p=0.30 use a binomial probability table to find the probability that the number of successes is exactly 4, at least2 and at most 3
We have a binomial experiment with n = 18 trials, each with probability p = 0.15...
We have a binomial experiment with n = 18 trials, each with probability p = 0.15 of a success. A success occurs if a student withdraws from a class, so the number of successes, x, will take on the values 0, 1, and 2. The probability of each x value, denoted f(x), can be found using a table like the one below. Note that these values are rounded to four decimal places. n x p 0.10 0.15 0.20 0.25 18...
A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n independent trials of he experiment.
A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n independent trials of he experiment. n=9, p=0.3, x≤3The probabity of x≤3 succenses is _______ (Round to four decimal places as needed.)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT