In: Chemistry
Reasonable efficiency for converting chemical energy to
electrical energy via combustion is 30%. Calculate how many pounds
of coal must be burned to run your reading lamp for two hours of
studying for a chemistry exam. A typical reading lamP has a 75 W
bulb. Assume that coal is pure graphite. (1 W = 1 J/s.)
_______lbs
Solution :-
Balanced reaction equation is as follows
C(s) + O2(g) -------> CO2(g)
the standard enthalpies of the C and O2 are zero kJ
and the CO2 = -393.5 kJ per mol
delta H reaction = Delta Hf product - Delta Hf reactant
= -393.5 kJ - (0 +0 )
= -393.5 kJ
therefore enthalpy of coimbustion of the Coal is -393 kJ per mol
Now lets calculate the energy needed for the lamp
(2 hour * 60 min / 1hr)*(60 s / 1 min)= 7200 s
75 W * 7200 s = 540000 W
540000 W * 1 J /s = 540000 J
540000 J * 1 kJ / 1000 J = 540 kJ
now lets calculate the mass of the coal
540 kJ * 12.01 g C / 393.5 kJ = 16.5 g C
now lets find the mass of coal using the percent efficiency
16.5 C * 100 % / 30.0 % = 55 g C
now lets convert gram to lb
55 g C * 1 lb / 453.5 g = 0.121 Lb
therefore we need 0.121 lb coal for the lamp to work for 2 hour