Question

Calculate delta H for melting exactly 1 gram of ice at exactly 0 degrees Celsius and 1 atm. Find delta U for this same process. Data: Heat of fusion for water 334.77 J/g. The desity of ice at 0C is 0.9168 g/mL and the density of water at 0C is 0.99984 g/mL. Ans: from the calculation, you should conclude that to 4 significant figures, delta H and delta U are the same. This is because the P(delta V) is very small for solid-liquid transitions.

Answer 1

E = H - RTn

but n = 0 in this process

thus:

E = H

G = H - TS

During the melting of ice it is in equilibrium with the liquid water, thus G is considered to be Zero. And heat need to be added inorder to the melt the ice, so it H is positive in nature. During this ice is converting into liquid form so it disorder increases so S will be negative.

G =0

H = TS

but G = 0

thus:

G