Question

In: Statistics and Probability

Based on historical data, your manager believes that 30% of the company's orders come from first-time...

Based on historical data, your manager believes that 30% of the company's orders come from first-time customers. A random sample of 77 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.34 and 0.47?

Solutions

Expert Solution

Solution:

Given that,

n = 77

= 30% =0.30

1 - = 1 - 0.30 = 0.70

=   = 0.30

= ( 1 - ) / n

=   0.30 * 0.70 / 77

= 0.0522

= 0.0522

p ( 0.34 <   < 0.47 )

p ( 0.34 - 0.30 / 0.0522 ) < ( -    / ) < ( 0.47 - 0.30 / 0.0522 )

p (0.04 / 0.0522 < z < 0.17 / 0.0522 )

p ( 0.77 < z < 3.26 )

p ( z < 3.26 ) - p ( z < 0.77 )

Using z table

= 0.9994 - 0.7794

= 0.2200

Probability = 0.2200


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