Question

Using standard reduction potential, predict and explain which of the following is the strongest reducing agent: Mg, I^-, Fe²⁺

If possible, please provide a detailed solution to accompany your answer.

Answer 1

The strengths of oxidizing and reducing agents are indicated by their standard electrode potentials

Cathode (Reduction) Half-Reaction	Standard Potential E° (volts)
Mg2+(aq) + 2e- -> Mg(s)	-                 -2.38

Fe²⁺(aq) + 2e^- -> Fe(s)                     -0.41

I₂ + 2e^- ---> 2I^-                                              +0.54

values for the table entries are reduction potentials, so Mg at the top of the list has the most negative number, indicating that it is the strongest reducing agent. Fe is next negative number implies second reducing agent. since The iodine is with positive number it is third reducing agent