Question

In: Physics

How much heat is required to change a 49.1 g ice cube from ice at -10.2°C...

How much heat is required to change a 49.1 g ice cube from ice at -10.2°C to water at 36°C? (if necessary, use cice=2090 J/kg°C and csteam= 2010 J/kg°C)

How much heat is required to change a 49.1 g ice cube from ice at -10.2°C to steam at 118°C?

Solutions

Expert Solution

1). Heat is needed first to raise the temperature of ice to 0 degree celsius then to convert ice into water then to raise the temperature of water from 0 degree celsius to 36 degree celsius.

then we'll have

  .................................(1)

where cice= specific heat of ice,

Tfc= Final Temperature of ice state

Tic= Initial Temperature of ice state

L= Latent Heat of fusion of ice into water, L= 334 J/gm

cwater= specific heat of water,

Tfw= Final Temperature of water state

Tiw= Initial Temperature of water state

Then using all above values and given values in equation 1,

  

  (ANS)............................(2)

2). Now on this process more heat will be needed to raise the temperature of converted water from 36 degree celsius to 100 degree celsius, then to convert it into steam and then finally to raise the temperature of steam to 118 degree celsius.

then ................(3)

where cwater= specific heat of water,

T'fw= Final Temperature of water state

Ti'w= Initial Temperature of water state after the process in 1st part

csteam= specific heat of steam,

Tfs= Final Temperature of steam

Tis= Initial Temperature of steam

Lvap= Latent Heat of vaporisation of water into steam, L= 2264.76 J/gm

Then using all the above values, given values and equation 2 in equation 3,

  

  

(ANS)


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