In: Statistics and Probability
Given
n = 12 , s = 0.326
The 99% confidence interval for the standard deviation PH of rain water in this region is
(n-1)*s2/
2a/2
<
<
(n-1)*s2/
21-a/2
For a = 0.01 , d.f = n -1 = 11
2
/2
, n-1 =
20.001 , 11 = 26.757
21-a/2
, n-1 =
20.995, 11 = 2.603
Sqrt[11*0.3262/26.757] <
< sqrt [11*0.3262/2.603]
0.209 <
< 0.670
we are 99% confident that the true standard deviation PH of rain water in this region lies between 0.209 to 0.670