Question
In: Statistics and Probability
A drapery store manager was interested in determining whether a new employee can install vertical blinds...
A drapery store manager was interested in determining whether a new employee can install vertical blinds faster than an employee who has been with the company for two years. The manager takes independent sample of 10 vertical blind on installations of each of the two employees and computes the following information. Test whether the new employee installs vertical blinds faster, on the average, than the veteran employee, at the level of significance 0.05.
| New Employee | Veteran Employee | |
| Sample Size | 10 | 10 |
| Sample Mean | 22.2 min | 24.8 min |
| Sample Standard Deviation | 0.90 min | 0.75 min |
Let
m1 = true average time takes a new employee to install vertical blinds
and
m2 = true average time takes a veteran employee to install vertical blinds
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orchestra answered 2 years agoRelated Solutions
A drapery store manager was interested in determining whether a new employee can install vertical blinds...
A drapery store
manager was interested in determining whether a new employee can
install vertical blinds faster than an employee who has been with
the company for two years. The manager takes independent sample of
10 vertical blind on installations of each of the two employees and
computes the following information. Test whether the new employee
installs vertical blinds faster, on the average, than the veteran
employee, at the level of significance 0.05.
New Employee
Veteran Employee
Sample Size
10...
A drapery store manager was interested in determining whether a new employee can install vertical blinds...
A drapery store manager was interested in determining whether a
new employee can install vertical blinds faster than an employee
who has been with the company for two years. The manager takes
independent samples of 10 vertical blind installations of each of
the two employees and computes the following information.
New Employee
Veteran Employee
Sample Size
10
10
Sample Mean
22.2 min
24.8 min
Standard Deviation
0.90 min
0.75 min
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