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A rocket is launched at an angle of 50.0° above the horizontal with an initial speed...

A rocket is launched at an angle of 50.0° above the horizontal with an initial speed of 95 m/s. The rocket moves for 3.00 s along its initial line of motion with an acceleration of 29.0 m/s2. At this time, its engines fail and the rocket proceeds to move as a projectile.

(a) Find the maximum altitude reached by the rocket.

(b) Find its total time of flight.

(c) Find its horizontal range.

(c) Find its horizontal range.

Solutions

Expert Solution

The answers are in the images. Page number is mentioned at right top. Here the given acceleration of the rocket is a = 29 m/s2 . As not clearly mentioned, as convention, here I consider this acceleration given here is considering the effect of gravitional acceleration, i.e net effect means the acceleration of rocket is given. If it is not, you just need to subtract the value of g from upward acceleration ay i.e (ay - g) = (22.21 - 9.81) = 12.4 as net upward acceleration and do the same method to solve the problem. However, as per problem statement and general convention, my calculation is right.

genius_generous answered 2 years ago
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