Question

Write a PHP script that checks a word or a phrase (stored in a string variable) to determine if it is a standard palindrome, a perfect palindrome, or not a palindrome at all. Also, for each letter that the word/phrase contains, count and print the number of times that each consonant and vowel is encountered. Your output will look as follows:

Word/phrase: racecar

Perfect palindrome

Contains consonants:

r - 2

c - 2

Contains vowels:

a - 2

e - 1

Answer 1

<?php
$word = "racecar";
echo "Word/phrase: $word<br>";
$reversed_word = strrev($word);
// converting to lower character after replacing special char
$refined_word = strtolower(preg_replace("([^A-Za-z0-9])", "", $word ));
$reversed = strtolower(strrev($refined_word));

if ($word === $reversed_word)
{
   echo "Perfect Palindrome<br>";
}
else{
   if ($refined_word == $reversed){
       echo "Standard Palindrome<br>";
   }
   else{
       echo "Not a palindrome<br>";
   }
}

$vowel = array('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U');

echo "Contains consonants:<br>";
foreach (count_chars($word, 1) as $strr => $value) {
   if (ctype_alpha(chr($strr)) &&(! in_array(chr($strr), $vowel))) {
       echo chr($strr) . " - $value <br>";
}
}

echo "Contains vowels:<br>";
foreach (count_chars($word, 1) as $strr => $value) {
   if (ctype_alpha(chr($strr)) &&(in_array(chr($strr), $vowel))) {
       echo chr($strr) . " - $value <br>";
}
}