How much water is displaced by 445g of fully submerged copper, SG= 8.9

Expert Solution

Specific Gravity is the ratio of the density of the substance to the density of water. SG = _S / _W

SG = _S / _W = (M_S / V_S) / (M_W / V_W) = (M_Sg / V_S) / (M_Wg / V_W) = (W_S / V_S) / (W_W / V_W)

The definition of SG was applied for the first equality; the definition of density was applied for the second equality. For the third equality, the numerator and denominator were multiplied by "g". W_S is the weight of the substance measured in air; W_W is the weight of the water displaced by the substance when it is immersed.

When a solid object is completely immersed in water, the volume of the water displaced must be equal to the volume of the object. (Vw = Vs)

So, SG = (W_S / V_S) / (W_W / V_W) = Ws / Ww

Therefore, water displaced, Ww = Ws / SG = 445 / 8.9 = 50g

genius_generous answered 2 years ago

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