A force of 95N is needed to push a 11kg object up a 37degree incline at...

A force of 95N is needed to push a 11kg object up a 37degree incline at a constant velocity. the block is then pushed down the incline and released. calculate the magnitude and direction of acceleration of the block after the release as it slides down the incline

Expert Solution

Here, frictional force = 95 - 11 * 9.8 * sin37

= 30.124 N

Thus, magnitude of net force on block as it slides down the incline = (11 * 9.8 * sin37 - 30.124)

= 34.751 N

Thus, magnitude of acceleration of the block as it slides down the incline = 34.751/11

= 3.159 m/s²

Direction of acceleration of the block = downwards

genius_generous answered 2 years ago

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