Question

In: Chemistry

What mass of ethylene glycol (C2H6O2) is required to lower the freezing point of 50.0 g...

What mass of ethylene glycol (C2H6O2) is required to lower the freezing point of 50.0 g of water by 10.0oC?

Expert Solution

Depression in freezing point = = 10 ^oC

K_f of ethylene glycol = 1.86

Formula to find depression in freezing point =

, Where m = molality of the solution

Molality of the solution =

Given mass of solvent = 50.0 g = 0.050 kg

So, now plugin molality and mass of solvent in the above formula

moles of ethylene glycol = 0.269 mol

Mass of ethylene glycol =

Mass of ethylene glycol (C₂H₆O₂) required = 16.7 g

queen_honey_blossom answered 2 years ago

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