A uniform magnetic field of strength .0050 T is directed out of the page. A wire...

A uniform magnetic field of strength .0050 T is directed out of the page. A wire oriented vertically in the field carries a current of 1.20 A up. a) Sketch the situation. b) Indicate the direction of the force on the wire. c) Find the magnitude of the force/length on the wire.

Solutions

Expert Solution

Given is:-

Magnetic field B = 0.0050T out of the page

Current in the wire I= 1.20A

Part-a

The sketch of the above mentioned situation is

Part-b

The force on the current carrying wire in a magnetic field is given by

thus the direction of the force is given by the cross product of the length vector (in the direction of the current) and the magnetic field. which can be found out by the Right Hand rule.

Thus

the direction of the Force in the given problem is

Thus the force is in +x direction or in right direction

Part-c

Magnitude of the force is

by plugging all the values we get

Thus the force per length is

Hence,

The magnitude of the force per length for the given problem is 0.006 N/m

genius_generous answered 1 year ago

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