In: Physics
A uniform magnetic field of strength .0050 T is directed out of the page. A wire oriented vertically in the field carries a current of 1.20 A up. a) Sketch the situation. b) Indicate the direction of the force on the wire. c) Find the magnitude of the force/length on the wire.
Given is:-
Magnetic field B = 0.0050T out of the page
Current in the wire I= 1.20A
Part-a
The sketch of the above mentioned situation is
Part-b
The force on the current carrying wire in a magnetic field is given by
thus the direction of the force is given by the cross product of the length vector (in the direction of the current) and the magnetic field. which can be found out by the Right Hand rule.
Thus
the direction of the Force in the given problem is
Thus the force is in +x direction or in right direction
Part-c
Magnitude of the force is
by plugging all the values we get
Thus the force per length is
Hence,
The magnitude of the force per length for the given problem is 0.006 N/m