In: Statistics and Probability
TEST THE APPROPRIATE HYPOTHESIS. Include the null and alternate hypotheses, degrees of freedom, test statistic, rejection region, and decision.
You roll a die 48 times. the results as followed
Number 1 2 3 4 5 6
Frequency 4 13 2 14 13 2
Use a significance level of 0.05 to test the claim that the die is fair
Solution:
Here, we have to use chi square test for goodness of fit.
Null hypothesis: H0: The die is fair.
Alternative hypothesis: Ha: The die is not fair.
We are given level of significance = α = 0.05
Test statistic formula is given as below:
Chi square = ∑[(O – E)^2/E]
Where, O is observed frequencies and E is expected frequencies.
We are given
Number of outcomes = N = 6
Degrees of freedom = df = N – 1 = 6 – 1 = 5
α = 0.05
Critical value = 11.07049775
(by using Chi square table or excel)
Rejection region: Reject H0 if χ2 statistic > 11.07049775
Calculation tables for test statistic are given as below:
Outcome |
O |
E |
(O - E)^2/E |
1 |
4 |
8 |
2 |
2 |
13 |
8 |
3.125 |
3 |
2 |
8 |
4.5 |
4 |
14 |
8 |
4.5 |
5 |
13 |
8 |
3.125 |
6 |
2 |
8 |
4.5 |
Total |
48 |
48 |
21.75 |
Test Statistic = Chi square = ∑[(O – E)^2/E] = 21.75
χ2 statistic = 21.75
P-value = 0.000584099
(By using Chi square table or excel)
P-value < α = 0.05
χ2 statistic > Critical value = 11.07049775
So, we reject the null hypothesis
Decision: Reject the null hypothesis
There is not sufficient evidence to conclude that the die is fair.