Question

In: Statistics and Probability

Hypothesis Testing – Indicate five steps in your answers (Null/alternate hypotheses, test-statistic, rejection area, decision for...

Hypothesis Testing – Indicate five steps in your answers (Null/alternate hypotheses, test-statistic, rejection area, decision for rejection, conclusion)

Randy is a famous pitcher in Long Island High School. His average throwing distance is 35 yards. However, his coach was analyzing Randy’s throwing angle and figuring how he had a bad habit to unconsciously lift his arm earlier than he was supposed to do. Coach trained Randy for his new strategy and measured his throwing distance that turned out to be 38 yards after 11 throws with a sample standard deviation of 5.2 yards. Coach is now believing that his new strategy is effective making Randy throw farther than 35 yards. Are these data providing sufficient evidence, at the 5% of level of significance, to conclude that coach’s strategy is effective? (throwing distances follows normal distribution)

Solutions

Expert Solution

The provided sample mean is 38 and the sample standard deviation is s = 5.2, and the sample size is n = 11

(1) Null and Alternative Hypotheses

The following null and alternative hypotheses need to be tested:

Null hypothesis:  coach’s strategy is not effective and his average throwing distance is 35 yards

Ho: μ = 35

Alternate hypothesis : coach’s strategy is effective and his average throwing distance is more than 35 yards

Ha: μ > 35

This corresponds to a right-tailed test, for which a t-test for one mean, with unknown population standard deviation will be used.

(2) Rejection Region

Based on the information provided, the significance level is α=0.05, and the critical value for a right-tailed test is t_c = 1.812

(3) Test Statistics

The t-statistic is computed as follows:

(4) Decision about the null hypothesis

Since it is observed that t = 1.913 >tc​=1.812, it is then concluded that the null hypothesis is rejected.

Using the P-value approach: The p-value is p = 0.0424, and since p = 0.0424 <0.05, it is concluded that the null hypothesis is rejected.

(5) Conclusion

It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that the population mean μ is greater than 35, at the 0.05 significance level.

Hence, coach’s strategy is effective and his average throwing distance is more than 35 yards


Related Solutions

Hypothesis Testing – Indicate five steps in your answers (Null/alternate hypotheses, test-statistic, rejection area, decision for...
Hypothesis Testing – Indicate five steps in your answers (Null/alternate hypotheses, test-statistic, rejection area, decision for rejection, conclusion) There are many grocery stores in New Jersey. The average number of customers checking out in each cashier register per ten minutes in all the grocery stores in New Jersey was 3.14 a year ago. Now, a marketer wishes to see if this number of customer is different now at the 5% of significance level. He visited 75 grocery stores and found...
Hypothesis Testing – Indicate five steps ion your answers (Null/alternate hypotheses, test-statistic, rejection area, decision for...
Hypothesis Testing – Indicate five steps ion your answers (Null/alternate hypotheses, test-statistic, rejection area, decision for rejection, conclusion) Companies in the beverage industry are in a keen competition to deliver more cans of beverages to retailers as fast as they can. What mostly determines how fast they are to deliver cans of beverage is the packing speed. The current amount the company named Orange Crusher delivers is 64.1 ounces. Quality inspector from this company is taking five packing machines and...
TEST THE APPROPRIATE HYPOTHESIS. Include the null and alternate hypotheses, degrees of freedom, test statistic, rejection...
TEST THE APPROPRIATE HYPOTHESIS. Include the null and alternate hypotheses, degrees of freedom, test statistic, rejection region, and decision. You roll a die 48 times. the results as followed Number 1 2 3 4 5 6 Frequency 4 13 2 14 13 2 Use a significance level of 0.05 to test the claim that the die is fair
For each question, write out the null and alternate hypotheses numerically. Give the test statistic and...
For each question, write out the null and alternate hypotheses numerically. Give the test statistic and p-value. Write out the equation of the test statistic but you do not have to evaluate it by hand. Then conclude with whether you reject or fail to reject the null hypothesis. Chapter 9 (Question 98.) Toastmasters International cites a report by Gallop Poll that 40% of Americans fear public speaking. A student believes that less than 40% of students at her school fear...
For each hypothesis test, you must state (a) hypotheses, (b) test statistic, p-value, (c) rejection rule,...
For each hypothesis test, you must state (a) hypotheses, (b) test statistic, p-value, (c) rejection rule, and (d) both parts of the conclusion. It is only necessary to calculate the effect size if the problem calls for it. Use a .05 level of significance for all hypothesis tests. Use StatCrunch to complete all hypothesis tests and confidence intervals. Make sure you copy and paste the relevant output for the solutions. Honor code expectations: you are not allowed any collaboration or...
What are the typical null and alternate hypotheses for a significance test on slope?
What are the typical null and alternate hypotheses for a significance test on slope?
1. For the standardized test statistic approach to hypothesis testing, calculate the test statistic for testing...
1. For the standardized test statistic approach to hypothesis testing, calculate the test statistic for testing the null hypothesis that the population mean is less than or equal to 9.29, given a sample mean of 13.90, a sample size of 35, and a population standard deviation of 3.92. Round to two decimals. 2. Using the traditional hypothesis testing approach, calculate the critical value for testing the null hypothesis that the population mean is greater than or equal to 13, given...
The decision rule (aka, the rejection region) for testing the following pair of hypotheses at the...
The decision rule (aka, the rejection region) for testing the following pair of hypotheses at the .01 level of significance when a sample size of 45 is taken. H0: p = .45 Ha: p ≠ .45 P (p̂ < 0.35) where p̂ is approximately normally distributed with p = .33 and n = 100. c. Determine the p-value for testing: H0: µ = 43 Ha: µ ≠ 43 when a random sample of size 30 was taken from a normal...
The decision rule (aka, the rejection region) for testing the following pair of hypotheses at the...
The decision rule (aka, the rejection region) for testing the following pair of hypotheses at the .01 level of significance when a sample size of 45 is taken. H0: p = .45 Ha: p ≠ .45 P (p̂ < 0.35) where p̂ is approximately normally distributed with p = .33 and n = 100. Determine the p-value for testing: H0: µ = 43 Ha: µ ≠ 43 when a random sample of size 30 was taken from a normal population...
Make sure you state your hypotheses and rejection rule. Calculate your test statistic and decide whether...
Make sure you state your hypotheses and rejection rule. Calculate your test statistic and decide whether to reject the null hypothesis or not and then explain what that conclusion means. You will need to use formulas with proper notation and draw diagrams for each of these problems. 2. From a population of coffee cans marked "12 ounces," a sample of 25 cans is selected and the contents of each can is weighed. The sample revealed a mean of 11.8 ounces...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT