In: Statistics and Probability
QUESTION 1
Which of the following would probably be a normal distribution with a positive skew? Check all that apply.
Housing prices |
||
Visits to the dentist in the past year |
||
Height |
||
Cigarettes smoked per day (in a county where most people don't smoke) |
20 points
QUESTION 2
What portion of a standard normal distribution is less than 1.5 standard deviations above the mean? (Express your answer as a number between zero and one, rounded to four decimal places.)
10 points
QUESTION 3
What portion of a standard normal distribution is less than 1.5 standard deviations above the mean andmore than 1.5 standard deviations below the mean? (Express your answer as a number between zero and one, rounded to four decimal places.)
10 points
QUESTION 4
Carla's company makes water heaters. These heaters last an average of 60 months, with a standard deviation of 8 months, before needing to be serviced. Her accountants estimate that the company can afford to replace 10% of all water heaters and still make a tidy profit.
Rounding to the nearest whole number, how many months should the warranty be?
20 points
QUESTION 5
If the margin of error for a confidence interval is 50 and the sample average is 160, what is the lower bound of the confidence interval?
5 points
QUESTION 6
If the margin of error for a confidence interval is 50 and the sample average is 160, what is the upper bound of the confidence interval?
5 points
QUESTION 7
Suppose you're estimating how much cloth you'll need to make a costume. If the margin of error of your confidence interval is 0.8 yards, what's the range of your confidence interval?
10 points
QUESTION 8
Suppose you want to estimate the sales per customer for the next holiday season. Based on past seasons, the population standard deviation is $60. Based on a survey sample of 36 people, you estimate this season each customer will spend an average of $900. At 95% confidence, what is the margin of error? Do not include a dollar sign ($) in your answer.
2)
P(Z ≤ 1.50 ) =
0.9332 (answer)
excel formula for probability from z score is
=NORMSDIST(Z)
3)
P ( -1.500 < Z <
1.500 )
= P ( Z < 1.500 ) - P ( Z
< -1.50 ) =
0.9332 - 0.0668 =
0.8664 (answer)
4)
µ= 60
σ = 8
P(X≤x) = 0.9000
Z value at 0.9 =
1.2816 (excel formula =NORMSINV(
0.9 ) )
z=(x-µ)/σ
so, X=zσ+µ= 1.282 *
8 + 60
X = 70.25
(answer)
5) lower bounds = sample mean - margin of error = 160-50 = 110
6) upper bounds = sample mean + margin of error = 160+50 = 210
7) range = 2*0.8 = 1.6
8)
Level of Significance , α =
0.05
' ' '
z value= z α/2= 1.960 [Excel
formula =NORMSINV(α/2) ]
Standard Error , SE = σ/√n = 60.0000 /
√ 36 = 10.0000
margin of error, E=Z*SE = 1.9600
* 10.0000 =
19.60