In: Statistics and Probability
QUESTION 1
Which of the following would probably be a normal distribution with a positive skew? Check all that apply.
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 Housing prices  | 
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 Visits to the dentist in the past year  | 
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 Height  | 
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 Cigarettes smoked per day (in a county where most people don't smoke)  | 
20 points
QUESTION 2
What portion of a standard normal distribution is less than 1.5 standard deviations above the mean? (Express your answer as a number between zero and one, rounded to four decimal places.)
10 points
QUESTION 3
What portion of a standard normal distribution is less than 1.5 standard deviations above the mean andmore than 1.5 standard deviations below the mean? (Express your answer as a number between zero and one, rounded to four decimal places.)
10 points
QUESTION 4
Carla's company makes water heaters. These heaters last an average of 60 months, with a standard deviation of 8 months, before needing to be serviced. Her accountants estimate that the company can afford to replace 10% of all water heaters and still make a tidy profit.
Rounding to the nearest whole number, how many months should the warranty be?
20 points
QUESTION 5
If the margin of error for a confidence interval is 50 and the sample average is 160, what is the lower bound of the confidence interval?
5 points
QUESTION 6
If the margin of error for a confidence interval is 50 and the sample average is 160, what is the upper bound of the confidence interval?
5 points
QUESTION 7
Suppose you're estimating how much cloth you'll need to make a costume. If the margin of error of your confidence interval is 0.8 yards, what's the range of your confidence interval?
10 points
QUESTION 8
Suppose you want to estimate the sales per customer for the next holiday season. Based on past seasons, the population standard deviation is $60. Based on a survey sample of 36 people, you estimate this season each customer will spend an average of $900. At 95% confidence, what is the margin of error? Do not include a dollar sign ($) in your answer.
2)
P(Z ≤   1.50   ) =  
0.9332   (answer)
excel formula for probability from z score is
=NORMSDIST(Z)
3)
P (    -1.500   < Z <   
1.500   )       
           
   
= P ( Z <    1.500   ) - P ( Z
<   -1.50   ) =   
0.9332   -    0.0668   =   
0.8664   (answer)
4)
µ=   60      
           
σ =    8      
           
P(X≤x) =   0.9000      
           
          
           
Z value at    0.9   =  
1.2816   (excel formula =NORMSINV(  
0.9   ) )
z=(x-µ)/σ          
           
so, X=zσ+µ=   1.282   *  
8   +   60  
X   =   70.25  
(answer)      
   
5) lower bounds = sample mean - margin of error = 160-50 = 110
6) upper bounds = sample mean + margin of error = 160+50 = 210
7) range = 2*0.8 = 1.6
8)
Level of Significance ,    α =   
0.05          
'   '   '      
   
z value=   z α/2=   1.960   [Excel
formula =NORMSINV(α/2) ]      
          
       
Standard Error , SE = σ/√n =   60.0000   /
√   36   =   10.0000
margin of error, E=Z*SE =   1.9600  
*   10.0000   =  
19.60