A chemist prepares a solution of mercury(I) chloride Hg2Cl2 by measuring out 0.0000059μmol of mercury(I) chloride...

A chemist prepares a solution of mercury(I) chloride Hg2Cl2 by measuring out 0.0000059μmol of mercury(I) chloride into a 50.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's mercury(I) chloride solution. Round your answer to 2 significant digits.

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Expert Solution

volume of solution = 50ml = 0.05L

no of moles of mercury(I) chloride Hg2Cl2 = 0.0000059μmol

= 0.0000059*10^-6mol [ μmol = 10^-6 mol]

molarity = no of moles/volume of solution in L

= 0.0000059*10^-6mol/0.05L

= 1.2*10^-10mol/L >>>>answer

the concentration in mol/L of the chemist's mercury(I) chloride solution= 1.2*10^-10 mol/L

queen_honey_blossom answered 1 year ago

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