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A chemist prepares a solution of mercury(I) chloride Hg2Cl2 by measuring out 0.0000059μmol of mercury(I) chloride...

A chemist prepares a solution of mercury(I) chloride Hg2Cl2 by measuring out 0.0000059μmol of mercury(I) chloride into a 50.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's mercury(I) chloride solution. Round your answer to 2 significant digits.

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Expert Solution

volume of solution = 50ml   = 0.05L

no of moles of mercury(I) chloride Hg2Cl2    = 0.0000059μmol    

                                                               = 0.0000059*10^-6mol                   [ μmol    = 10^-6 mol]

molarity   = no of moles/volume of solution in L

              = 0.0000059*10^-6mol/0.05L

               = 1.2*10^-10mol/L >>>>answer

the concentration in mol/L of the chemist's mercury(I) chloride solution= 1.2*10^-10 mol/L

queen_honey_blossom answered 2 years ago
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