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A brown Golder Retriever with short hair (dog X) is of an unknown genotype. To identify...

A brown Golder Retriever with short hair (dog X) is of an unknown genotype. To identify the genotype, a test cross was carried out between this dog and another Golder Retriever with light-color and long hair, both of which are known to be recessive traits. 50% of the F1 offspring from this cross are brown with short hair and the other 50% are light-coated with short hair.

A) What is the genotype of dog X? Explain your answer (you can use a Punnett square to check your answer) (5 points)

B) A cross between two individuals from the F1 generation, a brown dog with short hair (dog Y) and a light-coated dog with short hair (dog Z), is carried out and yield the F2 generation. Using a Punnett square, determine the yield of the F2 generation (both genotypes and phenotypes) and include the probability or percentage for each of the genotype and phenotype. (10 points)

Solutions

Expert Solution

1) The genotype of Dog X is AaBB.

Since the cross between this dog and another Golder Retriever with light-color and long hair produces 50% of the F1 offspring brown with short hair and the other 50% light-coated with short hair.

It is a dihybrid cross in which short hair and light color are dominant traits whereas long hair and brown color are recessive traits.

The genotype of Dog X is- AaBB (because in offspring recessive trait like brown color is present but long hair is absent which means, in Dog X gene for hair length is present in homozygous dominant form.

The genotype of another Golder Retriever is - aabb ( as it has recessive traits for both the characters)

AaBB/aabb ab
AB AaBb
aB aaBb

50% of the F1 offspring from this cross are brown with short hair ( aaBb) and the other 50% are light-coated with short hair (AaBb).

2)  A cross between two individuals from the F1 generation.

A brown dog with short hair (dog Y)- aaBb and a light-coated dog with short hair (dog Z)- AaBb

AaBb/aaBb aB ab
AB AaBB (light color, short hair) AaBb (light color, short hair)
Ab AaBb (light color, short hair) Aabb (light color, long hair)
aB aaBB (brown color, short hair) aaBb (brown color, short hair)
ab aaBb (brown color, short hair) aabb (brown color, long hair)

Ratio will be = 3:1:3:1

Probability for each of the genotype will be:-

AaBB- 1/8 , AaBb- 1/4, Aabb- 1/8, aaBB- 1/8, aaBb- 1/4, aabb- 1/8

Probability for each of the phenotype will be:-

light color, short hair- 3/8

light color, long hair - 1/8

brown color, short hair- 3/8

brown color, long hair- 1/8

gladiator answered 2 years ago
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