In: Operations Management
Use the Northwest Corner Rule to develop an initial solution to th transportation problem shown below. Present your answer in the following format. A to 1 = Qty X, B to 2 = Qty Y, etc
WHS 1 WHS 2 WHS 3 Capacity
Factory A 400
Factory B 300
Factory C 500
Demand 300 500 400
As per Northwest Corner Rule, we will follow below approach
Step1:Identify the cell at North-West corner of the transportation matrix.
Step 2: Allocate as many units as possible to that cell without exceeding supply or demand. Then remove out the row or column that is exhausted by this assignment
Step 3: Reduce the amount of corresponding supply or demand which is more by allocated amount.
Step 4: Again identify the North-West corner cell of reduced transportation matrix.
Step 5:Repeat Step 2 and Step 3 until all the requirements are satisfied.
WHS 1 | WHS 2 | WHS 3 | Capacity | |
Factory A | 400 | |||
Factory B | 300 | |||
Factory C | 500 | |||
Demands | 300 | 500 | 400 |
Start with north west corner for WHS 1 and Factory A capacity for allocation.
WHS 1 | WHS 2 | WHS 3 | Capacity | ||||
Factory A | 300 | 400 | |||||
Factory B | 300 | ||||||
Factory C | 500 | ||||||
Demands | 300 | 500 | 400 |
Then remove WHS 1 since demand is completed. 100 capacity from factory A is still left.
We move to next north west corner WHS 2 and factory A to start and then allocate as shown.
WHS 2 | WHS 3 | Capacity | |||
Factory A | 100 | 100 | |||
Factory B | 300 | 300 | |||
Factory C | 100 | 500 | |||
Demands | 500 | 400 |
In the step we cater for WHS 3 as shown
WHS 3 | Capacity | ||
Factory C | 400 | 400 | |
Demands | 400 |
Hence the optimal solution is
A to 1 = Qty 300
A to 2 = Qty 100,
B to 2 = Qty 300
C to 2 = Qty 100
C to 3 = Qty 400
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