Question

In an experiment, 11.5 grams of NO₂ gas are placed in a container at 30.00°C and 1.26 atm. What is the density of the gas?

Answer 1

Answer –

In this question we are given, mass of NO₂ = 11.5 g, T = 30.00 +273 = 303 K , P= 1.26 atm and we need to calculate the density of gas.

We know for the calculation of density we need mass and volume, we are given mass so we need to calculate from the given data

We know gas law-

PV = nRT

Step 1) calculate the moles of NO₂ from the given mass

We know formula

Moles = mass / molar mass

           = 11.5 g / 46.005 g.mol^-1

           = 0.250 moles

Step 2) Calculation of volume using th above gas law

PV = nRT

So, V = nRT / P

           = 0.250 moles *0.0821 L.atm.mol^-1.K^-1 * 303 K / 1.26atm

          = 4.935 L

Step 3) Calculate density

We know formula

Density = mass / volume

             = 11.5 g / 4.935 L

             = 2.33 g/L

The density of the gas is 2.33 g/L