In: Operations Management
a)
Demand | Probability | Cumulative probability |
1 | 0.25 | 0.25 < 0.9 |
2 | 0.25 | 0.50 < 0.9 |
3 | 0.25 | 0.75 < 0.9 |
4 | 0.25 | 1.00 > 0.9 |
So, the optimum order size for covering the demand in 90% cases = 4.
Average demand is 2.5,
So, safety stock = 4 - 2.5 = 1.5
b)
Demand | Probability | Cumulative probability |
3 | 0.333 | 0.333 < 0.9 |
4 | 0.333 | 0.667 < 0.9 |
5 | 0.333 | 1.000 > 0.9 |
So, the optimum order size for covering the demand in 90% cases = 5.
Average demand is 3,
So, safety stock = 5 - 3 = 2
c)
The safety stock will be just the sum of a) and b) i.e. 1.5+2 = 3.5
The order size has to be reported separately i.e. 4 and 5, we cannot add them. Adding them means nothing in real as they will be ordered separately.
d)
Market-1 | Market-2 | Total demand | Probability |
1 | 3 | 4 | 0.25 * 0.333 = 0.0833 |
1 | 4 | 5 | 0.0833 |
2 | 3 | 5 | 0.0833 |
1 | 5 | 6 | 0.0833 |
2 | 4 | 6 | 0.0833 |
3 | 3 | 6 | 0.0833 |
2 | 5 | 7 | 0.0833 |
3 | 4 | 7 | 0.0833 |
4 | 3 | 7 | 0.0833 |
3 | 5 | 8 | 0.0833 |
4 | 4 | 8 | 0.0833 |
4 | 5 | 9 | 0.0833 |
Combine the probability of the same total demand numbers in the following table and compute the cumulative probability after that only.
Total demand | Probability | Cumulative probability | Demand * prob |
4 | 0.0833 | 0.0833 | 0.333 |
5 | 0.1667 | 0.2500 | 0.833 |
6 | 0.2500 | 0.5000 | 1.500 |
7 | 0.2500 | 0.7500 < 0.9 | 1.750 |
8 | 0.1667 | 0.9167 > 0.9 | 1.333 |
9 | 0.0833 | 1.0000 | 0.750 |
Total | 1.0000 | 6.500 |
So, the optimum order size for covering the demand in 90% cases = 8.
Average demand is = 6.5,
So, safety stock = 8 - 6.5 = 1.5