Suppose the opcode of an MIPS instruction is 12 in decimal, and the rest of the...

Suppose the opcode of an MIPS instruction is 12 in decimal, and the rest of the machine code is 23483DB in hexadecimal (from high-order bit to low-order bit). What is the instruction? When showing the registers, use names (e.g. $t0, $s2) instead of indices (e.g $8, $17). For branch instructions, show offset in place of label, e.g. beq $t1, $t2, 92.

Solutions

Expert Solution

Hexadecimal     Binary
    0           0000
    1           0001
    2           0010
    3           0011
    4           0100
    5           0101
    6           0110
    7           0111
    8           1000
    9           1001
    A           1010
    B           1011
    C           1100
    D           1101
    E           1110
    F           1111
Use this table to convert from hexadecimal to binary
Converting 23483DB to binary
2 => 0010
3 => 0011
4 => 0100
8 => 1000
3 => 0011
D => 1101
B => 1011
So, in binary 23483DB is 10001101001000001111011011

opcode = 12
so, first 6 bits are 001100

instruction in binary is 001100 10001101001000001111011011

=>  00110010001101001000001111011011
=>  001100 10001  10100  1000001111011011
=>  opcode rs rt immediate
=>  ANDI   $s1    $s4    immediate

Converting 1000001111011011 to hexadecimal
1000 => 8
0011 => 3
1101 => D
1011 => B
So, in hexadecimal 1000001111011011 is 0x83DB

so, instruction is andi $s4, $s1, 0x83DB

Answer:
--------
andi $s4, $s1, 0x83DB

venereology answered 1 year ago

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