Question

Create a C++ project called RobberyLanguage. Ask the user to enter a word. Write a function that will receive the word, use the word to compile a new word in Robbery language and return the new Robbery language word. In the function: Use a while loop and a newline character (‘\0’) to step through the characters in the original string. How to compile a word in Robbery language: Double each consonant and put the letter ‘o’ between the two consonants. For example:" ENTER THE WORD: Welcome

original word is welcome , Robbery language: wowelolcocomome

process returned 0 (0*0) execution time :

press any key to continue "

Example of the definition of the function: string compileRobLanWord(char word[50]) Hints: Declare a new character string for the Robbery language word. A word in Robbery language has more characters than the original word. Therefor the new string must have its own index value. How it looks like in memory: Original word: S a m \0 2 0 1 2 3 Robbery language: S o S a m o m \0 0 1 2 3 4 5 6 7 Note: Remember to add the \0 character as the last character of the new word. In the main function: Example of the call statement in the main function: newWord = compileRobLanWord(word); Display the original word and the Robbery language word.

C#(VISUAL STUDIO)

Answer 1

#include<iostream>
#include<sstream>
#include<string>
using namespace std;

// FUNCTION PROTOTYPES
string compileRobLanWord(char word[50]);
bool isAlphabet(char c);
bool isConsonant(char c);

int main()
{
   char origWord[50];
   string robberyWord;
   cout << "ENTER THE WORD: ";
   cin >> origWord;
   robberyWord = compileRobLanWord(origWord);
   cout << "\nOriginal word is: " << origWord << endl;
   cout << "Robbery language is: " << robberyWord << endl;
   return 0;
}

// FUNCTION IMPLEMENTATIONS
string compileRobLanWord(char word[50])
{
   string res = "";
   stringstream ss;
   for (int i = 0; i < 50; i++)
   {
       if (isAlphabet(word[i]))
       {
           if (isConsonant(word[i]))
           {
               ss << word[i] << 'o' << word[i];
           }
           else
           {
               ss << word[i];
           }
       }
   }
   res = ss.str();
   return res;
}
bool isAlphabet(char c)
{
   if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z'))
       return true;
   else
       return false;
}
bool isConsonant(char c)
{
   if (c != 'A' && c != 'a' && c != 'E' && c != 'e' && c != 'I' && c != 'i' && c != 'O' && c != 'o' && c != 'U' && c != 'u')
       return true;
   else
       return false;
}

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