In: Statistics and Probability
The age distribution of the Canadian population and the age distribution of a random sample of 455 residents in the Indian community of a village are shown below.
Age (years) | Percent of Canadian Population | Observed
Number in the Village |
Under 5 | 7.2% | 46 |
5 to 14 | 13.6% | 85 |
15 to 64 | 67.1% | 281 |
65 and older | 12.1% | 43 |
Use a 5% level of significance to test the claim that the age distribution of the general Canadian population fits the age distribution of the residents of Red Lake Village.
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: The distributions are different.
H1: The distributions are the same.
H0: The distributions are different.
H1: The distributions are
different.
H0: The distributions are
the same.
H1: The distributions are the same.
H0: The distributions are the same.
H1: The distributions are different.
(b) Find the value of the chi-square statistic for the sample.
(Round your answer to three decimal places.)
Are all the expected frequencies greater than 5?
Yes
No
What sampling distribution will you use?
binomial
normal
chi-square
uniform
Student's t
What are the degrees of freedom?
(c) Estimate the P-value of the sample test statistic.
P-value > 0.100
0.050 < P-value < 0.100
0.025 < P-value < 0.050
0.010 < P-value < 0.025
0.005 < P-value < 0.010
P-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis that the population fits the
specified distribution of categories?
Since the P-value > α, we fail to reject the null hypothesis
.Since the P-value > α, we reject the null hypothesis.
Since the P-value ≤ α, we reject the null hypothesis.
Since the P-value ≤ α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the
application.
At the 5% level of significance, the evidence is insufficient to conclude that the village population does not fit the general Canadian population.
At the 5% level of significance, the evidence is sufficient to conclude that the village population does not fit the general Canadian population.
(a)
Level of significance = = 0.05
Correct option:
H0: The distributions are same.
H1: The distributions are different
(b)
Expected frequencies:
Under 5 | 455 X 7.2/100= 32.76 |
5 to 14 | 455 X 13.6/100 = 61.88 |
15 to 64 | 455 X 67.1/100 = 305.305 |
65 and older | 455 X 12.1/100 = 55.055 |
O | E | (O -E)2/E |
46 | 32.76 | 5.3510 |
85 | 61.88 | 8.6382 |
281 | 305.305 | 1.9349 |
43 | 55.055 | 2.6396 |
= 18.564
Are all xpected frequencies greater than 5:
Yes
Sampling Distribution:
Correct option:
Chi square
Degrees of freedom:
n - 1 = 4 - 1 = 3
(c)
By Technology,
p-value = 0.000336
So, correct option:
P-value < 0.005
(d)
Correct option:
Since the P-value , we reject the null hypothesis.
(e) Correct option:
At 5% level of significance the evidence is sufficient to conclude that the village population does not fit the general Canadian population.