In: Physics
an image is located -26.42cm from a concave lens. the magnification for this lens is 0.587. a) find the object distance. b) find the focal length
Image distance v = -26.42 cm
magnification of the lens m = 0.587
Object distance u = ?
We know m = v/ u
From this object distance u = v / m
= -26.42 / 0.587
= -45 cm
(b). Focal length f = ?
from the relation (1/u) +(1/v) = (1/f)
(1/-45)+(1/-26.42) = (1/f)
(1/f) = -0.06
f = -16.64 cm