1. A 0.3178 g sample of potassium hydrogen phthalate is dissolved in 100 mL of water....

1. A 0.3178 g sample of potassium hydrogen phthalate is dissolved in 100 mL of water. If 33.75 mL of sodium hydroxide solution are required to reach the equivalence point, what is the molarity of the sodium hydroxide solution?

2. Does the amount of water used to dissolve the KHP standard affect the calculated molarity of the sodium hydroxide? Explain why or why not.

Expert Solution

moles of KHP = mass / molar mass

= 0.3178 / 204.22

= 1.56 x 10^-3

KHP + NaOH -------------------------> KNaP + H2O

moles of KHP = moles of NaOH

moles of NaOH = 1.56 x 10^-3

molarity of NaOH = moles / volume

= 1.56 x 10^-3 / 33.75

= 0.0462 M

molarity of NaOH = 0.0462 M

2)

molarity of NaOH doesnot depends on the water amount . it only depends on moles of KHP . because its 1:1mole ratio problem

queen_honey_blossom answered 2 years ago

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