In: Statistics and Probability
A random sample n=30 is obtained from a population with unknown variance. The sample variance s2 = 100 and the sample mean is computed to be 75. Test the hypothesis at α = 0.05 that the population mean equals 80 against the alternative that it is less than 80. The null hypothesis Ho: µ = 80 versus the alternative H1: Ho: µ < 80.
Calculate the test statistic from your sample mean. Then calculate the p-value for this test using the test stat and the information about H1. Because you do not know the population variance, you should use Table A.2 for the t distribution to estimate the p-value. The p-value for this hypothesis test is approximately ____________%. Answer in percent form. For example, 5% should be written as 5.0 and 0.5% should be written as 0.005.
Note: drawing a picture of the t distribution and the values on Table A.2 can help you figure out the p-value from your test statistic.(PLEASE SHOW ME THE STEP)
Ho : µ = 80
Ha : µ < 80
(Left tail test)
Level of Significance , α =
0.050
sample std dev , s = 10.0000
Sample Size , n = 30
Sample Mean, x̅ = 75.0000
degree of freedom= DF=n-1= 29
Standard Error , SE = s/√n = 10.0000 / √
30 = 1.8257
t-test statistic= (x̅ - µ )/SE = (
75.000 - 80 ) /
1.8257 = -2.74
p-Value = 0.0052 [Excel formula
=t.dist(-2.74,29,true) ]
p value = 0.52%
Decision: p-value<α, Reject null hypothesis
Conclusion: There is enough evidence to conclude that true mean
is less than 80