In: Operations Management
1. If the learning curve for a process is 100 percent, the labor requirements in the company drop sharply. TRUE OR FALSE
2. If it took 1000 hours to produce the first unit of a product, and the learning curve is 70%, how long will it take to produce units 26 through 50?
Answer: ___________ hours (use whole number)
3. Under 80% learning rate, the improvement rate is _______ %
1. If learning curve of the process is 100 percent, then the time required to produce nth unit remains same as of the first unit. This means there is no improvement or no learning.
Y = aX^b
Y = cumulative time required to produce x units
a = time required to produce 1st unit
b = slope of the function or improvement rate
b = log (learning rate) / log 2 = log (1) / log (2) = 0/0.301= 0
now the equation is Y = aX^0 = a
As there is no learning, the time required to produce 1st unit is the time taken to produce nth unit. So, to produce any amount of units, we need that many times of number of labor required to produce 1st unit. Hence the labor requirement in the company increases sharply.
Answer is False.
2. a = 1000 hours, learning rate = 70%,
Y = aX^b
b = log (0.7)/log(2) = -0.51457
Y = 1000*26^(-0.51457) = 187 hours
Similarly the time can be calculated for units till 50.
units |
time required for nth unit |
cumulative till nth unit |
26 |
187.0239 |
187.0239 |
27 |
183.427 |
370.4509 |
28 |
180.0263 |
550.4771 |
29 |
176.8047 |
727.2819 |
30 |
173.7472 |
901.029 |
31 |
170.8402 |
1071.869 |
32 |
168.0718 |
1239.941 |
33 |
165.4315 |
1405.373 |
34 |
162.9097 |
1568.282 |
35 |
160.4977 |
1728.78 |
36 |
158.188 |
1886.968 |
37 |
155.9734 |
2042.941 |
38 |
153.8476 |
2196.789 |
39 |
151.8049 |
2348.594 |
40 |
149.8401 |
2498.434 |
41 |
147.9482 |
2646.382 |
42 |
146.125 |
2792.507 |
43 |
144.3664 |
2936.874 |
44 |
142.6687 |
3079.542 |
45 |
141.0284 |
3220.571 |
46 |
139.4424 |
3360.013 |
47 |
137.9077 |
3497.921 |
48 |
136.4218 |
3634.342 |
49 |
134.982 |
3769.324 |
50 |
133.586 |
3902.91 |
So, to produce units 26 through 50, it would require 3903 hours
3. Under 80% learning rate, the improvement rate is b = log(0.8)/log(2) = -0.32193 or -32%