Question

In: Chemistry

Sulfuric acid dissolves aluminum metal according to the following reaction: 2Al(s)+3H2SO4(aq)?Al2(SO4)3(aq)+3H2(g) Suppose you wanted to dissolve...

Sulfuric acid dissolves aluminum metal according to the following reaction: 2Al(s)+3H2SO4(aq)?Al2(SO4)3(aq)+3H2(g) Suppose you wanted to dissolve an aluminum block with a mass of 14.7g .

Part A

What minimum mass of H2SO4 would you need?

Express your answer in grams.

Part B

What mass of H2 gas would be produced by the complete reaction of the aluminum block?

Express your answer in grams.

Solutions

Expert Solution

2Al(s)+3H2SO4(aq)?Al2(SO4)3(aq)+3H2(g)

2x27g     3x 98g                                    3x2g

14.7g        ?                                           ?

a)

54g Al ----------------> 294g H2SO4                               

14.7g Al -------------------->        ?                

x = 294x14.7/54= 80.03

80.03g H2SO4     is needed

b)

54g Al --------------> 6g H2

14.7g-------------------?

x= 1.63g

1.63g H2 is produced


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