In: Physics
How do I fill the following table?
Use 3 significant figures and the accepted prefixes (kilo, mega, giga, tera, mili, micro, nano, etc.)
EM-WAVE RANGE (colour) | Wavelength | Frequency (Hz) | Energy (eV) | Temperature (K) |
Long radio waves | 1 km | |||
21 cm | ||||
2.7 K | ||||
5 cm | ||||
0.1 mm | ||||
0.01 mm | ||||
36.7 C | ||||
750 nm | ||||
Red | 660 nm | |||
550 nm | ||||
400 nm | ||||
380 nm | ||||
300 nm | ||||
200 nm | ||||
10 nm | ||||
0.1 nm | ||||
1 pm | ||||
1 fm | ||||
10^7 K |
To fill the blank spaces, use following relations:
E : Energy : Unit: Joules (J)
f = frequency : Unit : Hertz (Hz)
l = wavelength : Unit : meter (m)
T = temperature: Unit : Kelvin (K)
1. E = h*f
Where, h is planck's constant = 6.63 * 10-34 m2 kg/s
2. f * l = c
frequency * wavelength = speed of light
c: speed of light = 3 * 108 m/s
3. l = b/T (Wein's displacement law)
b: wein's displacement constant = 2.9 * 10-3 m K
Using any of the above three relations you can find the required values of l, f , E or T if any one is given.
1. Take the 1st row:
l = 1 km = 103 m
a) Thus, to find f, use l * f = c:
103 * f = 3 * 108
or,
f = 3 * 108 /103 = 3 * 105 Hz
b) To find E, use: E = h*f
E = 6.63 * 10-34 * 3 * 105 = 1.99 * 10-29 J
c) To find T, use: l = b/T
or, T = b / l = 2.9 * 10-3 / 1 = 2.9 * 10-3 K
Similarily we can find others:
2. l = 21 cm = 0.21 m
Thus, f = 3 * 108 / 0.21 = 1.43 * 109 Hz
E = 6.63 * 10-34 * 1.43 * 109 = 9.47 * 10-25 J
T = 2.9 * 10-3 / 0.21 = 1.38 * 10-2 K
3.
Here T = 2.7 K is given.
So we 1st find l:
l = b / T = 2.9 * 10-3 / 2.7 = 1.1 * 10-3 m
f = 3 * 108 / (1.1 * 10-3 ) = 2.73 * 1011 Hz
E = 6.63 * 10-34 * 2.73 * 1011 = 1.81 * 10-22 J
Similarily as shown above you can fill rest of the blanks
NOTE:
For T = 36.7 C, you have to convert 1st to Kelvin: T (K) = 274.15 + T (C)
So, 36.7 C = 274.15 +36.7 = 309.85 K