In: Physics
A dipole lies on the y axis and consists of an electron at y1 = 0.50nm and a proton at y2 = -0.50nm .
Part A
Find the electric field midway between the two charges.
Express your answer using two significant figures. Enter your answers numerically separated by a comma.
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Ex,Ey = | N/C |
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Part B
Find the electric field at the point x = -1.5nm , y = 0.
Express your answer using two significant figures. Enter your answers numerically separated by a comma.
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Ex,Ey = | N/C |
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Part C
Find the electric field at the point x = -26nm , y = 0.
Express your answer using two significant figures. Enter your answers numerically separated by a comma.
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Ex,Ey = | N/C |
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A similar question is solved below, but with different values. Please workout using your figures. Hope this helps you. Please rate me.
A dipole lies on the y axis, and consists of an electron at y =
0.50 nm and a proton at y = -0.50 nm. Find the electric field at
the following locations.
a) midway between the two charges
0 N/C i + _____ N/C j
(b) at the point x = 2.2 nm, y = 0
0 N/C i + _____ N/C j
(c) at the point x = -15 nm, y = 0
0 N/C i + _____ N/C j
resultant electric field E = 2kqa(a2 + x2)-3/2j^
charge q = 1.6*10-19 C
distance a = 0.5 nm = 0.5*10-9 m
constant k = 9*109 N.m2/C2
a)
midway between the two charges(x = 0):
electric field E = 0 N/C i^ + 2kqa(a2 + x2)-3/2j^
= 0 N/C i^ + 2kqa(a2 + 02)-3/2j^
= 0 N/C i^ + [2kq / (a)2 ]j^
= 0 N/C i^ + 2(9*109 N.m2/C2)(1.6*10-19 C) /(0.5*10-9 m)2
= 0 N/C i^ + 11.52*109 N/C j^
b)
at the point x = 2.2 nm, y = 0
electric field E = 2kqa((0.5*10-9 m)2 +
(2.2*10-9
m)2)-3/2j^
= 2kqa((0.25*10-18 m + 4.84 m*10-18 )-3/2j^
= 0 N/C i^ + 0.125*109 N/C j^
c)
at the point x = -15 nm, y = 0
electric field E = 2kqa((0.5*10-9 m)2 +
(-15*10-9
m)2)-3/2j^ =
2kqa((0.25*10-18 m + 225 m*10-18
)-3/2j^
= 4.26*105 N/C j^