Question

Java Question:

What is exception propagation? Give an example of a class that contains at least two methods, in which one method calls another. Ensure that the subordinate method will call a predefined Java method that can throw a checked exception. The subordinate method should not catch the exception. Explain how exception propagation will occur in your example.

Answer 1

`Hey,

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Exception propagation : An exception is first thrown from the top of the stack and if it is not caught, it drops down the call stack to the previous method.
After a method throws an exception, the runtime system attempts to find something to handle it. The set of possible “somethings” to handle the exception is the ordered list of methods that had been called to get to the method where the error occurred. The list of methods is known as the call stack and the method of searching is Exception

import java.io.IOException;

class Simple {

  

    // exception propagated to n()

    void m() throws IOException

    {

        // checked exception occurred

        throw new IOException("device error");

    }

  

    // exception propagated to p()

    void n() throws IOException

    {

        m();

    }

    void p()

    {

        try {

  

            // exception handled

            n();

        }

        catch (Exception e) {

            System.out.println("exception handled");

        }

    }

  

    public static void main(String args[])

    {

        Simple obj = new Simple();

        obj.p();

        System.out.println("normal flow...");

    }

}

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