In: Nursing
Your lab manager asks you to create the new control range for the new lot of hematology control level 1. The following 10 hemoglobin values are gathered to determine the control limits. Using a calculator or website SD function, calculate and record the mean, the standard deviation, and the 95% confidence interval for this set of values. (3 pts)
4.2, 4.7, 4.3, 4.4, 4.6, 4.7, 4.9, 5.0, 4.6, 4.0,
Mean:____4.54______ 1 SD:__0.2963______ 95% Confidence range (2 SD range):_____1.96___________
The given 10 values are
4.2, 4.7, 4.3, 4.4, 4.6, 4.7, 4.9, 5.0, 4.6, 4.0
Mean = sum of values / count = 45.4 / 10 = 4.54
Here the sample size is less than 30 hence n-1
(calculating the standard deviation)
Differences of each value from mean ---> -0.34, 0.16, -0.24, -0.14, 0.06, 0.16, 0.36, 0.46, 0.06, -0.54
Square of the differences ---> 0.1156, 0.0256, 0.0576, 0.0196, 0.0036, 0.0256, 0.1296, 0.2116, 0.0036, 0.2916
Adding them we get ---> 0.884
Dividing the value by count minus one ---> 0.884/(10-1) = 0.884/9 = 0.0982
Taking square root we get ---> 0.3134
Standard deviation = 0.3134
(calculating confidence interval)
Formula=>
t value for sample size 10 and confidence level 95% is 2.262
95% Confidence interval = 4.54 + - (2.262*0.3134/root10) =4.54 + - (0.7098/3.1622) = 4.54 + - 0.224 ---> 4.136 to 4.764
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