In: Statistics and Probability
Air traffic controllers perform the vital function of regulating the traffic of passenger planes. Frequently, air traffic controllers work long hours with little sleep. Researchers wanted to test thier ability to make basic decisions as they become increasingly sleep deprived. To test their abilities,a sample of 6 air traffic controllers is selected and given a decision-making skills test following 12 hour, 24 hour, and 48 hour sleep deprivation, Higher scores indicate better decision-making skills. The table list the hypothetical results of this study.
Sleep Deprivation
12 hours 24 hours 48 hours
24 19 17
20 22 22
35 23 23
28 22 14
24 15 17
21 21 16
(a) Complete the F table (Round your answers to two decimal places
Source of variation SS df MS Fbot
Between groups __ ___ ___ ___
Between persons ___ ____ ____
.w/in group error ____ ____ ____
total ____ ____
(b) Compute a Bonferroni procedure and interpret the results. ( Assume exoerimentwise alpha equal to 0.05. Select all that apply)
_ There are no significant differences between any of the group
_There is a significant difference in decision making for the 12 hour and 24 hour sleep deprivation condition
_ There is a significant difference in decision making for the 12 hour and 48 hour sleep deprivation condition
_ There is a significant difference in decision making for the 24 hour and 48 hour sleep deprivation conditions
using excel data analysis tool for two factor anova, following
o/p Is obtained : write data>menu>data>data
analysis>anova :two factor without replication>enter required
labels>ok, and following o/p Is obtained,
Anova: Two-Factor Without Replication | ||||||
SUMMARY | Count | Sum | Average | Variance | ||
subject 1 | 3 | 60 | 20 | 13.000 | ||
subject 2 | 3 | 64 | 21 | 1.333 | ||
subject 3 | 3 | 81 | 27 | 48.000 | ||
subject 4 | 3 | 64 | 21 | 49.333 | ||
subject 5 | 3 | 56 | 19 | 22.333 | ||
3 | 58 | 19 | 8.333 | |||
12 hours | 6 | 152 | 25 | 30.267 | ||
24 hours | 6 | 122 | 20 | 8.667 | ||
48 hours | 6 | 109 | 18 | 12.567 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Rows | 134.94 | 5 | 26.9889 | 2.202 | 0.1349 | 3.33 |
Columns | 162.11 | 2 | 81.0556 | 6.614 | 0.0148 | 4.10 |
Error | 122.56 | 10 | 12.2556 | |||
Total | 419.61 | 17 |
a)
SS | DF | MS | Fobt | |
between groups | 162.11 | 2 | 81.06 | 6.61 |
between persons | 134.94 | 5 | 26.99 | 2.20 |
error | 122.56 | 10 | 12.26 | |
total | 419.61 | 17 |
b)
The Bonferroni correction sets the significance cut-off at α/n where n is number of comparisons
α/n = 0.05/3 = 0.0167
Numerator d.f. | 3 |
Denominator d.f. | 10 |
MSE | 12.26 |
t-critical value,t(α/2,df) | 2.8701 |
bonferroni critical value=tα/2,df √(MSE(1/ni+1/nj)) = 5.80
confidence interval = mean difference ± critical value
if confidence interval contans zero, then means are not
different.
confidence interval | |||||||
population mean difference | critical value | lower limit | upper limit | result | |||
µ1-µ2 | 5.00 | 5.80 | -0.80 | 10.80 | means are not different | ||
µ1-µ3 | 7.17 | 5.80 | 1.37 | 12.97 | means are different | ||
µ2-µ3 | 2.17 | 5.80 | -3.63 | 7.97 | means are not different |
so,
_ There is a significant difference in decision making for the 12 hour and 48 hour sleep deprivation condition