Question

Using this 1000-digit string:
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450

Write the following method: public static int largestValue(String str)
1. Take a single String parameter
2. Work from the beginning to the end of the string,
3. identify the five-character group that represents the largest five-digit number.
4. The method is then to return the largest five digit value in the String as an integer.
Note:
1. Only one 5-digit group is to be identified and returned, so if two or more identical values are in the string, only one of those values is to be returned.
2. Each 5-digit group is built upon every single digit in the group (less the final four digits), so the first two five-digit groups will be the following: 73167, 31671, and so on. The last five-digit group will be 63450.
3. Must use the String class substring( ) method to solve the above problem.
4. The five-digit groups are to be evaluated as integers, and the value of the largest five-digit number is to be returned as an integer.

PLEASE HELP ME UNDERSTAND HOW TO COMPLETE THIS METHOD OR WHERE TO LEARN MORE I AM LOST HERE THANK YOU, BELOW IS WHAT A START:

public class Problem2StarterFile
{
public static void main(String [] args)
{
//variable declarations
String s = "73167176531330624919225119674426574742355349194934" +
"96983520312774506326239578318016984801869478851843" +
"85861560789112949495459501737958331952853208805511" +
"12540698747158523863050715693290963295227443043557" +
"66896648950445244523161731856403098711121722383113" +
"62229893423380308135336276614282806444486645238749" +
"30358907296290491560440772390713810515859307960866" +
"70172427121883998797908792274921901699720888093776" +
"65727333001053367881220235421809751254540594752243" +
"52584907711670556013604839586446706324415722155397" +
"53697817977846174064955149290862569321978468622482" +
"83972241375657056057490261407972968652414535100474" +
"82166370484403199890008895243450658541227588666881" +
"16427171479924442928230863465674813919123162824586" +
"17866458359124566529476545682848912883142607690042" +
"24219022671055626321111109370544217506941658960408" +
"07198403850962455444362981230987879927244284909188" +
"84580156166097919133875499200524063689912560717606" +
"05886116467109405077541002256983155200055935729725" +
"71636269561882670428252483600823257530420752963450";
   
System.out.println("The largest value is: " + largestValue(s));   
}

public static int largestValue(String str)
{
//PLEASE HELP ME UNDERSTAND HOW TO COMPLETE THIS METHOD OR WHERE TO LEARN MORE I AM LOST HERE THANK YOU
return(0);
}
}

Answer 1

public class Problem2StarterFile
{
public static void main(String [] args)
{
    //variable declarations
    String s = "73167176531330624919225119674426574742355349194934" +
    "96983520312774506326239578318016984801869478851843" +
    "85861560789112949495459501737958331952853208805511" +
    "12540698747158523863050715693290963295227443043557" +
    "66896648950445244523161731856403098711121722383113" +
    "62229893423380308135336276614282806444486645238749" +
    "30358907296290491560440772390713810515859307960866" +
    "70172427121883998797908792274921901699720888093776" +
    "65727333001053367881220235421809751254540594752243" +
    "52584907711670556013604839586446706324415722155397" +
    "53697817977846174064955149290862569321978468622482" +
    "83972241375657056057490261407972968652414535100474" +
    "82166370484403199890008895243450658541227588666881" +
    "16427171479924442928230863465674813919123162824586" +
    "17866458359124566529476545682848912883142607690042" +
    "24219022671055626321111109370544217506941658960408" +
    "07198403850962455444362981230987879927244284909188" +
    "84580156166097919133875499200524063689912560717606" +
    "05886116467109405077541002256983155200055935729725" +
    "71636269561882670428252483600823257530420752963450";
     
    System.out.println("The largest value is: " + largestValue(s));   
}

public static int largestValue(String str)
{
    // get length of the string
    int len = str.length();
    int i;
    String tmp;
    int res = Integer.MIN_VALUE; // initialize max value result to -infinity
    // read every 5 length substring and convert it to integer and assign result as maximum of result and this integer
    for(i = 0; i < len-5; i++){
     tmp = str.substring(i, i+5);
     res = Math.max(res, Integer.parseInt(tmp));
    }
    return res;
}
}

Approach is explained within comments.