Question

JAVA Write a program that translates a user-input floating-point number between 0 and 4 into the closest letter grade. For example, the number 2.8 (which might have been the average of several grades) would be converted to B–. Break ties in favor of the better grade; for example 2.85 should be a B. NOTE: Your implementation must include the definition/implementation and use/calling of the method numberGradeToLetterGrade that is passed a double numeric grade to its parameter variable, and returns the letter grade.

Answer 1

Answer :-

Definition

if grade >= 3.85 && grade <= 4.0 -> letterGrade = A+
if grade >= 3.5 && grade < 3.85 -> letterGrade = A

if grade >= 3.333 && grade < 3.5 -> letterGrade = A-
             

if grade >= 3.0 && grade < 3.333 -> letterGrade = B+
if grade >= 2.85 && grade < 3.0 -> letterGrade = B
   if grade >= 2.333 && grade < 2.85 -> letterGrade = B-
                 
if grade >= 2.0 && grade < 2.333 -> letterGrade = C+
     if grade >= 1.667 && grade < 2.0 -> letterGrade = C
    if grade >= 1.333 && grade < 1.667 -> letterGrade = C-

    if grade >= 1.0 && grade < 1.333 -> letterGrade = D+
    if grade > 0 && grade < 1.0 -> letterGrade = D
if grade == 0                 -> letterGrade = F
       

Java Code :-

import java.util.Scanner;
public class grade
{
  
    public static String numberGradeToLetterGrade(double number)
    {
        String letterGrade="N";
        if (number >= 3.85 && number <= 4.0 )
       {
           letterGrade = "A+";
       }
       else if (number >= 3.5 && number < 3.85 )
       {
           letterGrade = "A";
       }
       else if (number >= 3.333 && number < 3.5 )
       {
           letterGrade = "A-";
       }
       else if (number>= 3.0 && number < 3.333 )
       {
           letterGrade = "B+";
       }
       else if (number >= 2.85 && number < 3.0 )
       {
           letterGrade = "B";
       }  
       else if (number >= 2.333 && number < 2.85 )
       {
           letterGrade = "B-";
       }      
       else if (number >= 2.0 && number < 2.333 )
       {
           letterGrade = "C+";
       }      
       else if (number >= 1.667 && number < 2.0 )
       {
           letterGrade = "C";
       }      
       else if (number >= 1.333 && number < 1.667 )
       {
           letterGrade = "C-";
       }
       else if (number >= 1.0 && number < 1.333 )
       {
           letterGrade = "D+";
       }
       else if (number> 0 && number < 1.0 )
       {
           letterGrade = "D";
       }
       else if (number == 0)       {
           letterGrade = "F";
       }
       return letterGrade; // return letter Grade
    }
   public static void main(String[] args) {
   Scanner sc= new Scanner(System.in);
      
       System.out.print("Please enter your number between 0 and 4: ");// prompt the user for a number
  
       double number = sc.nextDouble();   // store the user input
      
       while (number <0 || number > 4) // if user not enter value between 0 to 4
       {
            System.out.print("Please enter your number between 0 and 4: ");
              
            number = sc.nextDouble(); // store the user input
       }
  
       String letterGrade;
       
        // now ,call a function numberGradeToLetterGrade and print letterGrade
        System.out.println("Your grade is\t" +number+ "\t Which is equal to: \t" + numberGradeToLetterGrade(number));
      
   }
}

Screenshot of code and output :-