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What is the molar solubility of nickel(II) sulfide in 0.053 M KCN? For NiS, Ksp =...

What is the molar solubility of nickel(II) sulfide in 0.053 M KCN? For NiS, K_sp = 3.0

Expert Solution

Ksp of NiS = 3.0 x 10^-19

Kf of Ni(CN)42- = 1.0 x 10^31

NiS (s) --------------> Ni2+ (aq) + S2- (aq)

Ni2+ (aq) + 4 CN- (aq) ------------> [Ni(CN)42-] (aq)

_______________________________________________

NiS (s) + 4 CN- (aq) ------------> [Ni(CN)42-] (aq) + S2- (aq)

Keq = Kf x Ksp

= 1.0 x 10^31 x 3.0 x 10^-19

= 3.0 x 10^12

NiS (s) + 4 CN- (aq) ------------> [Ni(CN)42-] (aq) + S2- (aq)

0.053 M 0 0

0.053-4x x x

Keq = x^2 / (0.053 - 4x)^4

3.0 x 10^12 = x^2 / (0.053 - 4x)^4

1.732 x 10^6 = x / (0.053 - 4x)^2

1.732 x 10^6 = x / 16 x^2 + 0.002809 - 0.424 x

2.77x 10^7 x^2 + 4865.2 - 734368 x = x

x = 0.01297

molar solubility = 1.3 x 10^-2 M

queen_honey_blossom answered 6 months ago

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