Question

Determine the area under the standard normal curve that lies to the left of ​(a)

Upper Z equals 0.08 commaZ=0.08,

​(b)

Upper Z equals 0.51Z=0.51​,

​(c)

Upper Z equals negative 1.15Z=−1.15​,

and ​(d)

Upper Z equals 0.56Z=0.56.

​(a) The area to the left of

Zequals=0.080.08

is

 

nothing.

​(Round to four decimal places as​ needed

Answer 1

a)

µ =    0      
σ =    1      
          
P( X ≤    0.08   ) = P( (X-µ)/σ ≤ (0.08-0) /1)  
=P(Z ≤   0.080   ) =   0.5319

b)

µ =    0      
σ =    1      
          
P( X ≤    0.51   ) = P( (X-µ)/σ ≤ (0.51-0) /1)  
=P(Z ≤   0.510   ) =   0.6950

c)

µ =    0      
σ =    1      
          
P( X ≤    -1.15   ) = P( (X-µ)/σ ≤ (-1.15-0) /1)  
=P(Z ≤   -1.150   ) =   0.1251

d)

µ =    0      
σ =    1      
          
P( X ≤    0.56   ) = P( (X-µ)/σ ≤ (0.56-0) /1)  
=P(Z ≤   0.560   ) =   0.7123