In: Physics
A contact lens is made of plastic with an index of refraction of
1.30. The lens has an outer radius of curvature of +1.96 cm and an
inner radius of curvature of +2.56 cm. What is the focal length of
the lens?
___cm
Given that
A contact lens is made of plasticwith an index of refraction of (n) = 1.30.
The lens has an outer radius of curvature of (R1) = +1.96 cm
And an inner radius of curvature of (R2) =+2.56cm.
Then the focal length of the lens is given by
1/f = (n-1)[1/R1 -1/R2]
=(1.30 -1)[1/1.96 -1/2.56]
=0.03587
Then f= 1/0.03587
=27.878 cm