Question

In: Statistics and Probability

Chapter 12 A researcher tested the number of mistakes made in a simulated driving test administered...

Chapter 12

A researcher tested the number of mistakes made in a simulated driving test administered 15 minutes after subjects in Group C ingested the equivalent of 1.5 ounces of alcohol within 30 minutes and Group B ingested the equivalent of 3.0 ounces of alcohol within 60 minutes. Subjects’ error scores are listed below.

               Group

Control                   3.0 ounces           1.5 ounces

     A                                   B                                 C

     3                                     9                               1

     1                                   10                              0

     5                                   15                              5

     0                                   11                              2

     2                                   12                              3

     0                                   14                              6

     1                                   15                              7

     1                             16                                    8

      2                            14                        4

  1. State the statistical hypothesis for this study.
  2. At p<.05, state the degrees of freedom and the critical value for this statistical test.
  3. Compute the F-ratio
  4. Make a decision and state your conclusion in APA format (review page 389 In The Literature).
  5. Indicate whether both or only one condition differs from the control group.

Chapter 13

Researchers randomly selected 5 college students and measured average minutes spent working out 8 weeks, 6 weeks, 4 weeks, and 2 weeks before Spring Break. They found the following results:

                                             Weeks

Subjects                 8              6              4              2
    A                             40            42            46            56

    B                             34            33            41            52

    C                             39            40            49            52

   D                             38            39            44            55

    E                              44            46            50            60

  1. State the statistical hypothesis for this study.
  2. At p<.01, state the degrees of freedom and the critical value for this statistical test.
  3. Compute the F-ratio
  4. Indicate effect size for this test.
  5. Make a decision and state your conclusion in APA format (review page 427 In The Literature).

Solutions

Expert Solution

12)

For the given data, using One-way ANOVA,

a)

The hypotheses are:

Ho: µ1 = µ2 = µ3 = µ4

H1: not all means are equal

b)

Degrees of freedom: DF1 = 2, DF2 = 24

Alpha = 0.05

F Critical value = 3.403 (Using calculator)

c) F-ratio value = 58.7655 = 58.766

d)

F- value > F- critical value, so we reject H0

Reject the null hypothesis. There is suffiecient evidence to conclude that all the means are not equal

13)

Ho: µ1=µ2=µ3=µ4
H1: not all means are equal

8 week 6 week 4 wek 2 week
count, ni = 5 5 5 5
mean , x̅ i = 39.000 40.00 40.00 55.00
std. dev., si = 3.606 4.743 12.186 3.32
sample variances, si^2 = 13.000 22.500 148.500 11.000
total sum 195 200 200 275 870 (grand sum)
grand mean , x̅̅ = Σni*x̅i/Σni =   43.50
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² 20.250 12.250 12.250 132.250
TOTAL
SS(between)= SSB = Σn( x̅ - x̅̅)² = 101.250 61.250 61.250 661.250 885
SS(within ) = SSW = Σ(n-1)s² = 52.000 90.000 594.000 44.000 780.0000

no. of treatment , k =   4
df between = k-1 =    3
N = Σn =   20
df within = N-k =   16
  
mean square between groups , MSB = SSB/k-1 =    295.0000
  
mean square within groups , MSW = SSW/N-k =    48.7500

anova table
SS df MS F p-value F-critical
Between: 885.00 3 295.00 6.05 0.0059 5.29
Within: 780.00 16 48.75
Total: 1665.00 19

       α =    0.01
conclusion :    p-value<α , reject null hypothesis        
.....

F
6.05

effect size =885.00/1665.00

=0.532

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