In: Statistics and Probability
Chapter 12
A researcher tested the number of mistakes made in a simulated driving test administered 15 minutes after subjects in Group C ingested the equivalent of 1.5 ounces of alcohol within 30 minutes and Group B ingested the equivalent of 3.0 ounces of alcohol within 60 minutes. Subjects’ error scores are listed below.
Group
Control 3.0 ounces 1.5 ounces
A B C
3 9 1
1 10 0
5 15 5
0 11 2
2 12 3
0 14 6
1 15 7
1 16 8
2 14 4
Chapter 13
Researchers randomly selected 5 college students and measured average minutes spent working out 8 weeks, 6 weeks, 4 weeks, and 2 weeks before Spring Break. They found the following results:
Weeks
Subjects                
8             
6             
4             
2
   
A          
                 
40           
42           
46           
56
B 34 33 41 52
C 39 40 49 52
D 38 39 44 55
E 44 46 50 60
12)
For the given data, using One-way ANOVA,

a)
The hypotheses are:
Ho: µ1 = µ2 = µ3 = µ4
H1: not all means are equal
b)
Degrees of freedom: DF1 = 2, DF2 = 24
Alpha = 0.05
F Critical value = 3.403 (Using calculator)
c) F-ratio value = 58.7655 = 58.766
d)
F- value > F- critical value, so we reject H0
Reject the null hypothesis. There is suffiecient evidence to conclude that all the means are not equal
13)
Ho: µ1=µ2=µ3=µ4
H1: not all means are equal
| 8 week | 6 week | 4 wek | 2 week | |||
| count, ni = | 5 | 5 | 5 | 5 | ||
| mean , x̅ i = | 39.000 | 40.00 | 40.00 | 55.00 | ||
| std. dev., si = | 3.606 | 4.743 | 12.186 | 3.32 | ||
| sample variances, si^2 = | 13.000 | 22.500 | 148.500 | 11.000 | ||
| total sum | 195 | 200 | 200 | 275 | 870 | (grand sum) | 
| grand mean , x̅̅ = | Σni*x̅i/Σni = | 43.50 | 
| square of deviation of sample mean from grand mean,( x̅ - x̅̅)² | 20.250 | 12.250 | 12.250 | 132.250 | |
| TOTAL | |||||
| SS(between)= SSB = Σn( x̅ - x̅̅)² = | 101.250 | 61.250 | 61.250 | 661.250 | 885 | 
| SS(within ) = SSW = Σ(n-1)s² = | 52.000 | 90.000 | 594.000 | 44.000 | 780.0000 | 
no. of treatment , k =   4
df between = k-1 =    3
N = Σn =   20
df within = N-k =   16
  
mean square between groups , MSB = SSB/k-1 =   
295.0000
  
mean square within groups , MSW = SSW/N-k =   
48.7500
| anova table | ||||||
| SS | df | MS | F | p-value | F-critical | |
| Between: | 885.00 | 3 | 295.00 | 6.05 | 0.0059 | 5.29 | 
| Within: | 780.00 | 16 | 48.75 | |||
| Total: | 1665.00 | 19 | 
       α =   
0.01
conclusion :    p-value<α , reject null hypothesis
       
.....
| F | 
| 6.05 | 
effect size =885.00/1665.00
=0.532
If you have any doubts please comment and please don't dislike.
PLEASE GIVE ME A LIKE. ITS VERY IMPORTANT FOR ME.