Question

JAVA

Write a test program that prompts the user to enter a list and displays whether the list is sorted or not. Here is a sample run. Note that the program first prompts the user to enter the size of the list. Using Array

My output should look like this

Enter the size of the list: 8

Enter the contents of the list: 10 1 5 16 61 9 11 1

The list has 8 integers 10 1 5 16 61 9 11 1

The list is not sorted

Answer 1

import java.util.*;

public class Main
{
   public static void main(String[] args) {
      
       Scanner s = new Scanner(System.in);
       System.out.println("Enter the size of the list : ");
       int n = s.nextInt();
       System.out.println("Enter the contents in the list : ");
       int a[] = new int[n];
       for(int i = 0; i < n; i++)
       {
       a[i] = s.nextInt();
       }
       int c1 = 0, c2 = 0;
       for(int i = 0; i < n - 1; i ++)
       {
       if(a[i] > a[i + 1])
       {
       c1++;
       }
       if(a[i] < a[i + 1])
       {
       c2++;
       }
       }
      
       if(c1 + 1 == n || c2 + 1 == n)
       {
       System.out.println("The list is sorted");
       }
       else{
       System.out.println("The list is not sorted");
       }

   }
}