Question

Sum

Bibi have an X × X array. Each array contains an integer a, and Bibi is curious about how much is the sum of all integers in each column.

Format Input:

The input consists of an integer T. The next T line contains X integers followed by an X × X array. Each array contains integers a.

Format Output

The output contains ”Case #T:” followed by X integers separated by spaces that indicate the sum of all the numbers in the i-th column.

Constraints

• 1 ≤ T ≤ 100

• 1 ≤ X ≤ 100

• 1 ≤ a ≤ 107

Sample Input 1 (standard input)

2

3

1 2 3

4 5 6

7 8 9

5

1 2 3 4 5

6 7 8 9 10

11 12 13 14 15

16 17 18 19 20

21 22 23 24 25

Sample Output 1 (standard output):

Case #1: 12 15 18

Case #2: 55 60 65 70 75

note : use c language, integer must be the same as the constraint, font use void/result code it under int main (){

Answer 1

All the explanations is given in the comments of the code itself.

Code--

#include<iostream>
using namespace std;
int main()
{
   int T,i;
   //prompt the user to give input fot T
   cin>>T;
   //declare an arry to store the output
   int output[T][100]={0};
   int size[T];
   i=0;
   //get inputs for each test case
   while(i<T)
   {
       int X;
       //prompt the user to give input fot X
       cin>>X;
       size[i]=X;
       //declare and int array of X x X
       int input[X][X];
       for(int a=0;a<X;a++)
       {
           for(int b=0;b<X;b++)
           {
               cin>>input[a][b];
           }
       }
       //calculate the sum of each column and save it in output array
       for(int a=0;a<X;a++)
       {
           for(int b=0;b<X;b++)
           {
               output[i][a]+=input[b][a];
           }
       }
       i++;
   }
   //display the output
   printf("\n\nOUTPUT:\n");
   for(i=0;i<T;i++)
   {
       printf("Case #%d: ",i+1);
       for(int j=0;j<size[i];j++)
       {
           printf("%d ",output[i][j]);
       }
       printf("\n");
   }
}
Code Screenshot--

Output Screenshot--

Note--

The output is presented in exact same way as you have requested for.

Please upvote if you like the effort.