In: Physics
The most energetic alpha particles available to Ernest Rutherford for his Rutherford scattering experiment were 7.7 MeV. For the scattering of 7.7 MeV alpha particles from 238U (initially at rest) at a scattering angle in the lab frame of 90 degrees, find the following: (All calculations are in the LAB system unless otherwise noted.)
a) The recoil scattering angle of 238U.
b) The scattering angles of the alpha particle and 238U in the CM system.
c) The kinetic energies of the scattered alpha particle and 238U.
d) The impact parameter b.
e) The distance of closest approach rmin.
f) The differential cross section at 90 degrees.
g) The ratio of the probabilities of scattering at 90 degrees to that of 5 degrees.