Question

hi! I have this code. when I run it, it works but in the print(the number we are searching for is ) it prints the number twice. ex. for 5 it prints 55 etc. apart from this, it works

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(){
int n,i;
printf("Give me the size of the table : \n");
scanf("%d", &n);
int A[n],x,y;

for (i=0;i<n;i++)
A[i]=rand() % n;

for (i=0;i<n;i++)
printf("%d\n", A[i]);

srand(time(NULL));
y=rand()% n ;

printf("The number we are searching for is %d", y);

for (i=0;i<n;i++)
{
    if (A[i]==y)
    {
      printf("%d is present at location %d.\n", y,i+1);
      break;
    }
}
if (i == n)
    printf("%d isn't present in the array.\n", y);

return 0;
}

Answer 1

The code is working fine. but displaying two times of the number searching so that it is displaying two times.

please take a look on the code corrected code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(){
   int n,i;
   srand(time(0));
   printf("Give me the size of the table : \n");
   scanf("%d", &n);
   int A[n];
   int x,y;
  
   for (i=0;i<n;i++)
       A[i] = rand()%n;
  
   for (i=0;i<n;i++)
       printf("%d\n", A[i]);

   srand(time(NULL));
   y=rand()%n; //random generate number upto n numbers
   //do not have to display here the y value if display then
   //not display in the inside for loop in print statement
   printf("The number we are searching for is ");
   for (i=0;i<n;i++) //loop to the n times
   {
        if (A[i]==y) //check for the index value is same as y value
        {
          //here is printed again the y value so that it is displaying two times the value corrected
          printf("%d is present at location %d.\n", y,i+1); //prints the found with the index
          break; //breaks the loop
        }
   }
   if (i == n) //if not found
        printf("%d isn't present in the array.\n", y);
  
   return 0;
}

sample output: