Question

c++

input 10 number and calclute the midrange using (largest - smallest)/2.0. use for loop

note : dont use arrays

Answer 1

#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
    //declare the variables
    //assign 0 to max and 99999999 (large number) to min
int max=0,min=99999999,i,n;
double midrange;
//loop to accept 10 values
for(i=0;i<10;i++)  
{
   cout<<endl<<"Enter a number";
   cin>>n;//read the number from user
   if(max<n) //condition for finding the largest value
   max=n;
   if(min>n)//condition for finding the smallest value
   min=n;
}
midrange = (double)(max-min)/2; //compute the midrange value
//print the midrange value
cout<<endl<<"Midrange Value : "<<fixed<<setprecision(2)<<midrange;
}

output