Question

What would the output be for the following program code segment?

#define ROWS  3     

#define COLS 3

void addCoulmns(int arr[][COLS],int Sum[COLS]);

int main(void)

{

       int array[ROWS][COLS] = {{ 10, 35, 23 },

                                  { 5, 4, 57 },

                                  { 4, 7, 21 }};

       int ColSum[ROWS];

       int rows;

       int columns;

       addCoulmns(array,ColSum);

       for (columns = 0; columns < COLS - 1; columns++)

              printf("%d\n",ColSum[columns]);

       return(0);

}

void addCoulmns(int arr[][COLS],int Sum[COLS])

{

       int row;

       int col;

       for (col = 0; col < COLS - 1; col++)

       {

              Sum[col] = 0;

              for (row = 0; row < ROWS - 1; row++)

                      Sum[col] += arr[row][col];

       }

       return;

}

Answer 1

Output:

15
39

Short Explanation:

In main function we are calling a function called addCoulmns(array,ColSum) here ColSum is a array of integer

Inside the addCoulmns function there is a for loop which iterate till ROWS-1 which means 3-1=2, So in first iteration Sum[col] which is equivalent to ColSum 1st iteration of outer loop and 1st of inner loop row=0,col=0 so Sum[0]=arr[0][0]+ Sum[0] so Sum[0]=10+0 //(0 because we have initialize Sum[]=0 at first). 2nd iteration of inner loop row=1 col=0 Sum[0]=arr[1][0]+Sum[0] which is Sum[0]=5+10=15

Therefore Sum[0]=15 and now 2nd iteration of outer loop 1st iteration of inner loop will be row=0 col=1 Sum[1]=arr[0][1]+Sum[1] which is Sum[1]=35+0 so Sum[1]=35 now 2nd iteration in inner for loop row=1 col=1 , Sum[1]=arr[1][1]+Sum[1] which is Sum[1]=4+35=39

Sum[0]=15 Sum[1]=39

Inside main() again

COLS has value 3 we are iterating in for loop which is in main up to COLS-1 which means 3-1=2. So the loop will iterate 2 times, Inside for loop we have print statement which prints a value which is most probably integer printing value of array named ColSum which is equivalent to Sum so ColSum has value 15 39

Col[0]=15 Col[1]=39