Question

represent 8912 in 16-bit binary format and then convert it to Hexadecimal form.

Answer 1

Since this is a positive number. we can directly convert this into binary
Divide 8912 successively by 2 until the quotient is 0
   > 8912/2 = 4456, remainder is 0
   > 4456/2 = 2228, remainder is 0
   > 2228/2 = 1114, remainder is 0
   > 1114/2 = 557, remainder is 0
   > 557/2 = 278, remainder is 1
   > 278/2 = 139, remainder is 0
   > 139/2 = 69, remainder is 1
   > 69/2 = 34, remainder is 1
   > 34/2 = 17, remainder is 0
   > 17/2 = 8, remainder is 1
   > 8/2 = 4, remainder is 0
   > 4/2 = 2, remainder is 0
   > 2/2 = 1, remainder is 0
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 10001011010000
So, 8912 of decimal is 10001011010000 in binary
Adding 2 zeros on left hand side of this number to make this of length 16
so, 8912 in 2's complement binary is 0010001011010000
Hexadecimal     Binary
    0           0000
    1           0001
    2           0010
    3           0011
    4           0100
    5           0101
    6           0110
    7           0111
    8           1000
    9           1001
    A           1010
    B           1011
    C           1100
    D           1101
    E           1110
    F           1111
Use this table to convert from binary to hexadecimal
Converting 0010001011010000 to hexadecimal
0010 => 2
0010 => 2
1101 => D
0000 => 0
So, in hexadecimal 0010001011010000 is 0x22D0
Answer: 0x22D0