Question

PLEASE ANSWER IN C

Assume that an int variable age has been declared and already given a value and assume that a char variable choice has been declared as well. Assume further that the user has just been presented with the following menu:

• S: hangar steak, red potatoes, asparagus
• T: whole trout, long rice, brussel sprouts
• B: cheddar cheeseburger, steak fries, cole slaw

(Yes, this menu really IS a menu!)

Write some code that reads a single character (S or T or B) into choice. Then the code prints out a recommended accompanying drink as follows:

If the value of age is 21 or lower, the recommendation is "vegetable juice" for steak, "cranberry juice" for trout, and "soda" for the burger. Otherwise, the recommendations are "cabernet", "chardonnay", and "IPA" for steak, trout, and burger respectively. Regardless of the value of age, your code should print "invalid menu selection" if the character read into choice was not S or T or B.

Answer 1

• #include <stdio.h>

  int main()

  {

  int age;

  printf("Enter the age: ");

  scanf("%d", &age);//taking input for the age

  //following is to print the menu

  printf("S: hangar steak, red potatoes, asparagus\nT: whole trout, long rice, brussel sprouts\nB: cheddar cheeseburger, steak fries, cole slaw\n");

  printf("\nEnter your choice: ");//asking user for choice

  while(getchar()!='\n');//clearing the input buffer

  char c;

  scanf("%c", &c);//taking the input of choice

  printf("\n\n");

  //following is to print the desired output

  if(c=='S')

  {

  if(age<=21)

  {

  printf("Vegetable Juice\n");

  }

  else printf("Cabernet\n");

  }

  else if(c=='T')

  {

  if(age<=21)printf("cranberry juice\n");

  else printf("chardonnay\n");

  }

  else if(c=='B')

  {

  if(age<=21)printf("soda\n");

  else printf("IPA\n");

  }

  else

  {

  printf("invalid menu selection\n");

  }

  }

//Code Ends Here